2020-04-27 08:15:23 +00:00
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// poly34.h : solution of cubic and quartic equation
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// (c) Khashin S.I. http://math.ivanovo.ac.ru/dalgebra/Khashin/index.html
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// khash2 (at) gmail.com
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#ifndef POLY_34
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#define POLY_34
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#include "LinearMath/btScalar.h"
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// x - array of size 2
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// return 2: 2 real roots x[0], x[1]
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// return 0: pair of complex roots: x[0]i*x[1]
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2020-12-17 12:51:12 +00:00
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int SolveP2(btScalar* x, btScalar a, btScalar b); // solve equation x^2 + a*x + b = 0
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2020-04-27 08:15:23 +00:00
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// x - array of size 3
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// return 3: 3 real roots x[0], x[1], x[2]
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// return 1: 1 real root x[0] and pair of complex roots: x[1]i*x[2]
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2020-12-17 12:51:12 +00:00
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int SolveP3(btScalar* x, btScalar a, btScalar b, btScalar c); // solve cubic equation x^3 + a*x^2 + b*x + c = 0
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2020-04-27 08:15:23 +00:00
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// x - array of size 4
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// return 4: 4 real roots x[0], x[1], x[2], x[3], possible multiple roots
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// return 2: 2 real roots x[0], x[1] and complex x[2]i*x[3],
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// return 0: two pair of complex roots: x[0]i*x[1], x[2]i*x[3],
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2020-12-17 12:51:12 +00:00
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int SolveP4(btScalar* x, btScalar a, btScalar b, btScalar c, btScalar d); // solve equation x^4 + a*x^3 + b*x^2 + c*x + d = 0 by Dekart-Euler method
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2020-04-27 08:15:23 +00:00
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// x - array of size 5
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// return 5: 5 real roots x[0], x[1], x[2], x[3], x[4], possible multiple roots
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// return 3: 3 real roots x[0], x[1], x[2] and complex x[3]i*x[4],
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// return 1: 1 real root x[0] and two pair of complex roots: x[1]i*x[2], x[3]i*x[4],
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2020-12-17 12:51:12 +00:00
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int SolveP5(btScalar* x, btScalar a, btScalar b, btScalar c, btScalar d, btScalar e); // solve equation x^5 + a*x^4 + b*x^3 + c*x^2 + d*x + e = 0
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2020-04-27 08:15:23 +00:00
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//-----------------------------------------------------------------------------
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// And some additional functions for internal use.
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// Your may remove this definitions from here
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2020-12-17 12:51:12 +00:00
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int SolveP4Bi(btScalar* x, btScalar b, btScalar d); // solve equation x^4 + b*x^2 + d = 0
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int SolveP4De(btScalar* x, btScalar b, btScalar c, btScalar d); // solve equation x^4 + b*x^2 + c*x + d = 0
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void CSqrt(btScalar x, btScalar y, btScalar& a, btScalar& b); // returns as a+i*s, sqrt(x+i*y)
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btScalar N4Step(btScalar x, btScalar a, btScalar b, btScalar c, btScalar d); // one Newton step for x^4 + a*x^3 + b*x^2 + c*x + d
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btScalar SolveP5_1(btScalar a, btScalar b, btScalar c, btScalar d, btScalar e); // return real root of x^5 + a*x^4 + b*x^3 + c*x^2 + d*x + e = 0
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2020-04-27 08:15:23 +00:00
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#endif
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