Fixed wrong example in JSONParseResult.
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Data class wrapper for decoded JSON.
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</brief_description>
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<description>
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Returned by [method JSON.parse], [code]JSONParseResult[/code] contains decoded JSON or error information if JSON source not successfully parsed. You can check if JSON source was successfully parsed with [code]if json_result.error == 0[/code].
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Returned by [method JSON.parse], [code]JSONParseResult[/code] contains decoded JSON or error information if JSON source not successfully parsed. You can check if JSON source was successfully parsed with [code]if json_result.error == OK[/code].
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</description>
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<tutorials>
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</tutorials>
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@ -26,9 +26,9 @@
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A [Variant] containing the parsed JSON. Use typeof() to check if it is what you expect. For example, if JSON source starts with curly braces ([code]{}[/code]) a [Dictionary] will be returned, if JSON source starts with braces ([code][][/code]) an [Array] will be returned.
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[i]Be aware that the JSON specification does not define integer or float types, but only a number type. Therefore, parsing a JSON text will convert all numerical values to float types.[/i]
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[codeblock]
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p = JSON.parse('["hello", "world", "!"]')
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if typeof(p) == TYPE_ARRAY:
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print(p[0]) # prints 'hello'
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var p = JSON.parse('["hello", "world", "!"]')
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if typeof(p.result) == TYPE_ARRAY:
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print(p.result[0]) # prints 'hello'
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else:
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print("unexpected results")
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[/codeblock]
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