Robustify multi-threading primitives
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20ed51a912
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6189ab5291
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@ -1178,14 +1178,30 @@ void Thread::_start_func(void *ud) {
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String func_name = t->target_callable.is_custom() ? t->target_callable.get_custom()->get_as_text() : String(t->target_callable.get_method());
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::Thread::set_name(func_name);
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// To avoid a circular reference between the thread and the script which can possibly contain a reference
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// to the thread, we will do the call (keeping a reference up to that point) and then break chains with it.
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// When the call returns, we will reference the thread again if possible.
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ObjectID th_instance_id = t->get_instance_id();
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Callable target_callable = t->target_callable;
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t = Ref<Thread>();
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Callable::CallError ce;
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t->target_callable.callp(nullptr, 0, t->ret, ce);
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if (ce.error != Callable::CallError::CALL_OK) {
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Variant ret;
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target_callable.callp(nullptr, 0, ret, ce);
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// If script properly kept a reference to the thread, we should be able to re-reference it now
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// (well, or if the call failed, since we had to break chains anyway because the outcome isn't known upfront).
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t = Ref<Thread>(ObjectDB::get_instance(th_instance_id));
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if (t.is_valid()) {
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t->ret = ret;
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t->running.clear();
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ERR_FAIL_MSG("Could not call function '" + func_name + "' to start thread " + t->get_id() + ": " + Variant::get_callable_error_text(t->target_callable, nullptr, 0, ce) + ".");
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} else {
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// We could print a warning here, but the Thread object will be eventually destroyed
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// noticing wait_to_finish() hasn't been called on it, and it will print a warning itself.
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}
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t->running.clear();
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if (ce.error != Callable::CallError::CALL_OK) {
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ERR_FAIL_MSG("Could not call function '" + func_name + "' to start thread " + t->get_id() + ": " + Variant::get_callable_error_text(t->target_callable, nullptr, 0, ce) + ".");
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}
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}
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Error Thread::start(const Callable &p_callable, Priority p_priority) {
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@ -33,6 +33,9 @@
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#include "core/error/error_list.h"
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#include "core/typedefs.h"
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#ifdef DEBUG_ENABLED
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#include "core/error/error_macros.h"
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#endif
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#include <condition_variable>
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#include <mutex>
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@ -42,6 +45,9 @@ private:
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mutable std::mutex mutex;
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mutable std::condition_variable condition;
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mutable uint32_t count = 0; // Initialized as locked.
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#ifdef DEBUG_ENABLED
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mutable uint32_t awaiters = 0;
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#endif
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public:
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_ALWAYS_INLINE_ void post() const {
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@ -52,10 +58,16 @@ public:
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_ALWAYS_INLINE_ void wait() const {
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std::unique_lock lock(mutex);
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#ifdef DEBUG_ENABLED
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++awaiters;
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#endif
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while (!count) { // Handle spurious wake-ups.
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condition.wait(lock);
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}
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count--;
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--count;
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#ifdef DEBUG_ENABLED
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--awaiters;
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#endif
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}
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_ALWAYS_INLINE_ bool try_wait() const {
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@ -67,6 +79,47 @@ public:
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return false;
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}
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}
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#ifdef DEBUG_ENABLED
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~Semaphore() {
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// Destroying an std::condition_variable when not all threads waiting on it have been notified
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// invokes undefined behavior (e.g., it may be nicely destroyed or it may be awaited forever.)
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// That means other threads could still be running the body of std::condition_variable::wait()
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// but already past the safety checkpoint. That's the case for instance if that function is already
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// waiting to lock again.
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//
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// We will make the rule a bit more restrictive and simpler to understand at the same time: there
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// should not be any threads at any stage of the waiting by the time the semaphore is destroyed.
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//
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// We do so because of the following reasons:
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// - We have the guideline that threads must be awaited (i.e., completed), so the waiting thread
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// must be completely done by the time the thread controlling it finally destroys the semaphore.
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// Therefore, only a coding mistake could make the program run into such a attempt at premature
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// destruction of the semaphore.
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// - In scripting, given that Semaphores are wrapped by RefCounted classes, in general it can't
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// happen that a thread is trying to destroy a Semaphore while another is still doing whatever with
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// it, so the simplification is mostly transparent to script writers.
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// - The redefined rule can be checked for failure to meet it, which is what this implementation does.
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// This is useful to detect a few cases of potential misuse; namely:
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// a) In scripting:
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// * The coder is naughtily dealing with the reference count causing a semaphore to die prematurely.
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// * The coder is letting the project reach its termination without having cleanly finished threads
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// that await on semaphores (or at least, let the usual semaphore-controlled loop exit).
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// b) In the native side, where Semaphore is not a ref-counted beast and certain coding mistakes can
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// lead to its premature destruction as well.
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//
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// Let's let users know they are doing it wrong, but apply a, somewhat hacky, countermeasure against UB
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// in debug builds.
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std::lock_guard lock(mutex);
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if (awaiters) {
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WARN_PRINT(
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"A Semaphore object is being destroyed while one or more threads are still waiting on it.\n"
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"Please call post() on it as necessary to prevent such a situation and so ensure correct cleanup.");
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// And now, the hacky countermeasure (i.e., leak the condition variable).
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new (&condition) std::condition_variable();
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}
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}
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#endif
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};
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#endif // SEMAPHORE_H
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@ -101,7 +101,9 @@ Thread::Thread() {
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Thread::~Thread() {
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if (id != UNASSIGNED_ID) {
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#ifdef DEBUG_ENABLED
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WARN_PRINT("A Thread object has been destroyed without wait_to_finish() having been called on it. Please do so to ensure correct cleanup of the thread.");
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WARN_PRINT(
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"A Thread object is being destroyed without its completion having been realized.\n"
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"Please call wait_to_finish() on it to ensure correct cleanup.");
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#endif
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thread.detach();
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}
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@ -5,6 +5,11 @@
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</brief_description>
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<description>
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A synchronization mutex (mutual exclusion). This is used to synchronize multiple [Thread]s, and is equivalent to a binary [Semaphore]. It guarantees that only one thread can ever acquire the lock at a time. A mutex can be used to protect a critical section; however, be careful to avoid deadlocks.
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It's of the recursive kind, so it can be locked multiple times by one thread, provided it also unlocks it as many times.
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[b]Warning:[/b]
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To guarantee that the operating system is able to perform proper cleanup (no crashes, no deadlocks), these conditions must be met:
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- By the time a [Mutex]'s reference count reaches zero and therefore it is destroyed, no threads (including the one on which the destruction will happen) must have it locked.
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- By the time a [Thread]'s reference count reaches zero and therefore it is destroyed, it must not have any mutex locked.
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</description>
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<tutorials>
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<link title="Using multiple threads">$DOCS_URL/tutorials/performance/using_multiple_threads.html</link>
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@ -29,6 +34,7 @@
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<description>
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Unlocks this [Mutex], leaving it to other threads.
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[b]Note:[/b] If a thread called [method lock] or [method try_lock] multiple times while already having ownership of the mutex, it must also call [method unlock] the same number of times in order to unlock it correctly.
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[b]Warning:[/b] Calling [method unlock] more times that [method lock] on a given thread, thus ending up trying to unlock a non-locked mutex, is wrong and may causes crashes or deadlocks.
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</description>
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</method>
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</methods>
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@ -5,6 +5,10 @@
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</brief_description>
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<description>
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A synchronization semaphore which can be used to synchronize multiple [Thread]s. Initialized to zero on creation. Be careful to avoid deadlocks. For a binary version, see [Mutex].
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[b]Warning:[/b]
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To guarantee that the operating system is able to perform proper cleanup (no crashes, no deadlocks), these conditions must be met:
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- By the time a [Semaphore]'s reference count reaches zero and therefore it is destroyed, no threads must be waiting on it.
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- By the time a [Thread]'s reference count reaches zero and therefore it is destroyed, it must not be waiting on any semaphore.
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</description>
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<tutorials>
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<link title="Using multiple threads">$DOCS_URL/tutorials/performance/using_multiple_threads.html</link>
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@ -6,6 +6,11 @@
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<description>
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A unit of execution in a process. Can run methods on [Object]s simultaneously. The use of synchronization via [Mutex] or [Semaphore] is advised if working with shared objects.
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[b]Note:[/b] Breakpoints won't break on code if it's running in a thread. This is a current limitation of the GDScript debugger.
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[b]Warning:[/b]
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To guarantee that the operating system is able to perform proper cleanup (no crashes, no deadlocks), these conditions must be met by the time a [Thread]'s reference count reaches zero and therefore it is destroyed:
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- It must not have any [Mutex] objects locked.
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- It must not be waiting on any [Semaphore] objects.
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- [method wait_to_finish] should have been called on it.
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</description>
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<tutorials>
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<link title="Using multiple threads">$DOCS_URL/tutorials/performance/using_multiple_threads.html</link>
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