Require `return` in all match branches
Before the parser only checked if the catch-all branch has a return in order to determine if the entire match block has a return. This code block was assumed to always return. match value: "test": print("test") _: return Now as soon as one of the branches has no return, the entire match block is marked to not have a return.
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@ -2211,6 +2211,8 @@ GDScriptParser::PatternNode *GDScriptParser::_parse_pattern(bool p_static) {
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void GDScriptParser::_parse_pattern_block(BlockNode *p_block, Vector<PatternBranchNode *> &p_branches, bool p_static) {
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void GDScriptParser::_parse_pattern_block(BlockNode *p_block, Vector<PatternBranchNode *> &p_branches, bool p_static) {
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int indent_level = tab_level.back()->get();
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int indent_level = tab_level.back()->get();
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p_block->has_return = true;
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while (true) {
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while (true) {
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while (tokenizer->get_token() == GDScriptTokenizer::TK_NEWLINE && _parse_newline())
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while (tokenizer->get_token() == GDScriptTokenizer::TK_NEWLINE && _parse_newline())
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@ -2268,8 +2270,8 @@ void GDScriptParser::_parse_pattern_block(BlockNode *p_block, Vector<PatternBran
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current_block = p_block;
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current_block = p_block;
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if (catch_all && branch->body->has_return) {
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if (!branch->body->has_return) {
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p_block->has_return = true;
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p_block->has_return = false;
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}
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}
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p_branches.push_back(branch);
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p_branches.push_back(branch);
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