Merge pull request #74730 from MarioLiebisch/fix-74726
Fix read-only dictionaries adding missing keys
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commit
867ea7fe59
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@ -83,9 +83,16 @@ Variant &Dictionary::operator[](const Variant &p_key) {
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if (unlikely(_p->read_only)) {
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if (p_key.get_type() == Variant::STRING_NAME) {
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const StringName *sn = VariantInternal::get_string_name(&p_key);
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*_p->read_only = _p->variant_map[sn->operator String()];
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const String &key = sn->operator String();
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if (likely(_p->variant_map.has(key))) {
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*_p->read_only = _p->variant_map[key];
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} else {
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*_p->read_only = Variant();
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}
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} else if (likely(_p->variant_map.has(p_key))) {
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*_p->read_only = _p->variant_map[p_key];
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} else {
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*_p->read_only = Variant();
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}
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return *_p->read_only;
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@ -88,6 +88,12 @@ TEST_CASE("[Dictionary] Assignment using bracket notation ([])") {
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CHECK(int(map[0]) == 400);
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// Check that assigning 0 doesn't overwrite the value for `false`.
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CHECK(int(map[false]) == 128);
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// Ensure read-only maps aren't modified by non-existing keys.
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const auto length = map.size();
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map.make_read_only();
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CHECK(int(map["This key does not exist"].get_type()) == Variant::NIL);
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CHECK(map.size() == length);
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}
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TEST_CASE("[Dictionary] get_key_lists()") {
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