Fixed wrong example in JSONParseResult.

(cherry picked from commit 24e87f97c6)
This commit is contained in:
Michael Alexsander Silva Dias 2018-02-04 19:52:27 -02:00 committed by Hein-Pieter van Braam
parent d4a70c6c08
commit a0e9d751a3
1 changed files with 4 additions and 4 deletions

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@ -4,7 +4,7 @@
Data class wrapper for decoded JSON.
</brief_description>
<description>
Returned by [method JSON.parse], [code]JSONParseResult[/code] contains decoded JSON or error information if JSON source not successfully parsed. You can check if JSON source was successfully parsed with [code]if json_result.error == 0[/code].
Returned by [method JSON.parse], [code]JSONParseResult[/code] contains decoded JSON or error information if JSON source not successfully parsed. You can check if JSON source was successfully parsed with [code]if json_result.error == OK[/code].
</description>
<tutorials>
</tutorials>
@ -27,9 +27,9 @@
[i]Be aware that the JSON specification does not define integer or float types, but only a number type. Therefore, parsing a JSON text will convert all numerical values to float types.
Note that JSON objects do not preserve key order like Godot dictionaries, thus you should not rely on keys being in a certain order if a dictionary is constructed from JSON. In contrast, JSON arrays retain the order of their elements:[/i]
[codeblock]
p = JSON.parse('["hello", "world", "!"]')
if typeof(p) == TYPE_ARRAY:
print(p[0]) # prints 'hello'
var p = JSON.parse('["hello", "world", "!"]')
if typeof(p.result) == TYPE_ARRAY:
print(p.result[0]) # prints 'hello'
else:
print("unexpected results")
[/codeblock]