GDScript: Don't use validated call for vararg methods
Since they may have runtime type validation, we cannot use the validated call.
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@ -1058,7 +1058,7 @@ void GDScriptByteCodeGenerator::write_call_gdscript_utility(const Address &p_tar
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void GDScriptByteCodeGenerator::write_call_utility(const Address &p_target, const StringName &p_function, const Vector<Address> &p_arguments) {
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bool is_validated = true;
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if (Variant::is_utility_function_vararg(p_function)) {
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is_validated = true; // Vararg works fine with any argument, since they can be any type.
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is_validated = false; // Vararg needs runtime checks, can't use validated call.
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} else if (p_arguments.size() == Variant::get_utility_function_argument_count(p_function)) {
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bool all_types_exact = true;
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for (int i = 0; i < p_arguments.size(); i++) {
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@ -1107,7 +1107,7 @@ void GDScriptByteCodeGenerator::write_call_builtin_type(const Address &p_target,
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// Check if all types are correct.
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if (Variant::is_builtin_method_vararg(p_type, p_method)) {
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is_validated = true; // Vararg works fine with any argument, since they can be any type.
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is_validated = false; // Vararg needs runtime checks, can't use validated call.
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} else if (p_arguments.size() == Variant::get_builtin_method_argument_count(p_type, p_method)) {
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bool all_types_exact = true;
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for (int i = 0; i < p_arguments.size(); i++) {
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@ -1,4 +1,4 @@
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func test():
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var lambda := func(unused: Variant) -> void:
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pass
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lambda.call()
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lambda.call("something")
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